DLMF:10.5.E5 (Q3028)

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DLMF:10.5.E5
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    test
    𝒲 ⁡ { H ν ( 1 ) ⁡ ( z ) , H ν ( 2 ) ⁡ ( z ) } = H ν + 1 ( 1 ) ⁡ ( z ) ⁢ H ν ( 2 ) ⁡ ( z ) - H ν ( 1 ) ⁡ ( z ) ⁢ H ν + 1 ( 2 ) ⁡ ( z ) = - 4 ⁢ i / ( π ⁢ z ) . Wronskian Hankel-H-1-Bessel-third-kind 𝜈 𝑧 Hankel-H-2-Bessel-third-kind 𝜈 𝑧 Hankel-H-1-Bessel-third-kind 𝜈 1 𝑧 Hankel-H-2-Bessel-third-kind 𝜈 𝑧 Hankel-H-1-Bessel-third-kind 𝜈 𝑧 Hankel-H-2-Bessel-third-kind 𝜈 1 𝑧 4 𝑖 𝜋 𝑧 {\displaystyle{\displaystyle\mathscr{W}\left\{{H^{(1)}_{\nu}}\left(z\right),{H% ^{(2)}_{\nu}}\left(z\right)\right\}={H^{(1)}_{\nu+1}}\left(z\right){H^{(2)}_{% \nu}}\left(z\right)-{H^{(1)}_{\nu}}\left(z\right){H^{(2)}_{\nu+1}}\left(z% \right)=-4i/(\pi z).}}
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    DLMF:10.5.E5
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